Unless you live in a isolation chamber you’ll already know that despite Oxford’s best efforts to support Labour the results of the European elections in the South-East region of which we are part are that we have

• 4 UKIP
• 3 Conservative
• 1 Green
• 1 Labour
• 1 LibDem

MEPs.

The good news is they are all on twitter, so you can raise any issues you like with them in 140 characters or less. Here they are in alphabetical order. Hit those ‘Follow’ buttons now!

Name	Party	twitter
Richard Ashworth	Con	@RichardAshMEP
Janice Atkinson	UKIP	@JaniceUKIP
Catherine Bearder	LibDem	@catherineMEP
Nirj Deva	Con	@NirjDeva
Annaliese Dodds	Lab	@AnnelieseDodds
Nigel Farage	UKIP	@Nigel_Farage
Ray Finch	UKIP	@raymondfinch
Dan Hannan	Con	@DanHannanMEP
Diane James	UKIP	@DianeUKIP
Keith Taylor	Green	@GreenKeithMEP

I realised I didn’t have a clue how the voting works in the European elections, so as part of my dedicated efforts to make life just a little bit easier for all my loyal readers I researched it and now bring you the fruits of my labours.

Here in Oxford we’re part of the South-east Region. Ten MEPs will be elected to represent us. But you will only have ONE vote – one X on the ballot paper – on 22 May. You vote for a party not an individual. Each of the main competing parties has produced a list of 10 candidates (smaller parties may have fewer): candidates are elected in turn starting at the top of the party’s list. The candidates’ names will be on the ballot paper but there will be no other information about them – do your research first! Individuals can stand too, and the voting system treats them as if they were a party with only one candidate on the list.

Here is the official record of who is standing. The UKPollingReport website has a complete and also more colourful version giving some information about some of the candidates.

This is a mock-up of what the ballot paper will look like, courtesy of Southampton Council’s Returning Officer.

So how does your one vote get transformed into 10 elected MEPs? Here’s how.

All the votes are counted. The first candidate on the list of the party with the most votes is elected. The number of votes for that party are then divided by a scale factor of 2. The party which now has the highest number of votes has their first candidate elected and their votes scaled by dividing by 2.

This process continues. If a second candidate is elected from a party’s list their original number of votes is now scaled by dividing by 3 (not 2). In fact every time a candidate is elected his/her party’s votes are scaled by first 2, then 3, then 4 and so on.

This table shows a simulated example.

We start with the parties sorted by the number of votes they received. Party A has the most votes so their first candidate is elected, indicated by the red block. In the next column Party A’s votes are scaled by dividing by 2, meaning they now have 11728 counting votes. Party B now have the highest number, so their first candidate is elected (red block), and their votes are scaled down to 9333. Third place goes to Party C, fourth to Party D.

By the time we get to the fifth place, Party A’s scaled votes are again the highest number, so Party A’s second candidate is elected. Their original vote is now scaled by 3, becoming 7819. And so on, with following places going to Party B, Party A again, Party C, Party E (for the first time), and finally Party D.

So we end up with Party A having 3 seats, Parties B, C and D with 2 and Party E with 1, making ten in all.

So that’s it. Simple really, isn’t it?